JS Sortir berdasarkan Properti
list.sort((a, b) => (a.color > b.color) ? 1 : -1)
Jittery Jaguar
list.sort((a, b) => (a.color > b.color) ? 1 : -1)let x = list.sort((a, b) => (a.name > b.name ? 1 : -1));function compareFirstNames( a, b ) {
if ( a.first_name < b.first_name ){
return -1;
}
if ( a.first_name > b.first_name ){
return 1;
}
return 0;
}
var people =[
{"first_name":"Carol", "age":29},
{"first_name":"Anna", "age":32},
{"first_name":"Bob", "age":32}
];
people.sort( compareFirstNames ); //people is now sorted by first name from a-zfunction sortByDate( a, b ) {
if ( a.created_at < b.created_at ){
return -1;
}
if ( a.created_at > b.created_at ){
return 1;
}
return 0;
}
myDates.sort(sortByDate);//myDates is not sorted.objs.sort((a,b) => (a.last_nom > b.last_nom) ? 1 : ((b.last_nom > a.last_nom) ? -1 : 0))1
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var employees=[]
employees[0]={name:"George", age:32, retiredate:"March 12, 2014"}
employees[1]={name:"Edward", age:17, retiredate:"June 2, 2023"}
employees[2]={name:"Christine", age:58, retiredate:"December 20, 2036"}
employees[3]={name:"Sarah", age:62, retiredate:"April 30, 2020"}