“JavaScript mengurutkan array objek berdasarkan properti secara abjad” Kode Jawaban

Urutkan Objek JavaScript Abjad

//Sort object by v1 property alphabetically (case insensitive)
let objArray= [
  {v1:"Bee", v2: 2}, 
  {v1:"Apple", v2: 8}, 
  {v1:"bat", v2: 4},
];
let sortedArray= objArray.sort(function(a, b) {
   return a.v1.localeCompare(b.v1);
}); // [{v1: "Apple", v2: 8}, {v1: "bat", v2: 2}, {v1: "Bee", v2: 2}]
Gubo97000

Urutkan array objek berdasarkan nilai properti string

function compareFirstNames( a, b ) {
  if ( a.first_name < b.first_name ){
    return -1;
  }
  if ( a.first_name > b.first_name ){
    return 1;
  }
  return 0;
}

var people =[
    {"first_name":"Carol", "age":29},
    {"first_name":"Anna", "age":32},
    {"first_name":"Bob", "age":32}
];

people.sort( compareFirstNames ); //people is now sorted by first name from a-z
Grepper

Urutkan Objek JavaScript Abjad

objArray.sort(function(a, b) {
    var textA = a.DepartmentName.toUpperCase();
    var textB = b.DepartmentName.toUpperCase();
    return (textA < textB) ? -1 : (textA > textB) ? 1 : 0;
});
Crazy Cockroach

JS mengurutkan sifat objek secara abjad

const data = {
  States: ['NSW', 'VIC'],
  Countries: ['GBR', 'AUS'],
  Capitals: ['SYD', 'MEL']
}

const sortedObject = Object.fromEntries(Object.entries(data).sort())
Index out of bounds

JavaScript mengurutkan array objek berdasarkan properti secara abjad

var data = [{ h_id: "3", city: "Dallas", state: "TX", zip: "75201", price: "162500" }, { h_id: "4", city: "Bevery Hills", state: "CA", zip: "90210", price: "319250" }, { h_id: "6", city: "Dallas", state: "TX", zip: "75000", price: "556699" }, { h_id: "5", city: "New York", state: "NY", zip: "00010", price: "962500" }];

data.sort(function (a, b) {
    return a.city.localeCompare(b.city) || b.price - a.price;
});

console.log(data);
Tiny Coders

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