“JavaScript mengurutkan array objek berdasarkan tanggal” Kode Jawaban

JavaScript Sorts On Objects Tanggal

array = [{
  			id: 1, name: "test1", date: "2020-01-05",
			id: 2, name: "test2", date: "2020-01-02"
		}]

array.sort(function (a, b) {
	var dateA = new Date(a.date), dateB = new Date(b.date)
	return dateA - dateB
});

console.log(array) //array is now sorted by date
Embarrassed Emu

JavaScript mengurutkan array objek berdasarkan tanggal

// Price Low To High
array?.sort((a, b) => (a.price > b.price ? 1 : -1))
// Price High To Low
array?.sort((a, b) => (a.price > b.price ? -1 : 1))
// Name A to Z
array?.sort((a, b) => (a.name > b.name ? 1 : 1))
// Name Z to A
array?.sort((a, b) => (a.name > b.name ? -1 : 1))
// Sort by date
array.sort((a,b) =>  new Date(b.date) - new Date(a.date));
ashirbad-panigrahi

Array pesanan JavaScript berdasarkan tanggal

const sortedActivities = activities.sort((a, b) => b.date - a.date)
Kind Kestrel

Urutkan serangkaian objek JavaScript berdasarkan tanggal

array.sort(function(a,b){
  // Turn your strings into dates, and then subtract them
  // to get a value that is either negative, positive, or zero.
  return new Date(b.date) - new Date(a.date);
});
Brave Bee

JS memesan array objek berdasarkan tanggal

 arr = arr.sort(function (a, b) {
      var dateA = new Date(a.date_prop).getTime();
      var dateB = new Date(b.date_prop).getTime();
      return dateA < dateB ? 1 : -1;
    });
Muddy Mole

Bagaimana cara mengurutkan array objek berdasarkan properti tanggal?

// Simplest Answer
array.sort(function(a,b){
  // Turn your strings into dates, and then subtract them
  // to get a value that is either negative, positive, or zero.
  return new Date(b.date) - new Date(a.date);
});

// -------------------

// More Generic Answer
array.sort(function(o1,o2){
  if (sort_o1_before_o2)    return -1;
  else if(sort_o1_after_o2) return  1;
  else                      return  0;
});

// Or more tersely:

array.sOr more tersely:ort(function(o1,o2){
  return sort_o1_before_o2 ? -1 : sort_o1_after_o2 ? 1 : 0;
});
// -------------------

// Generic, Powerful Answer
(function(){
  if (typeof Object.defineProperty === 'function'){
    try{Object.defineProperty(Array.prototype,'sortBy',{value:sb}); }catch(e){}
  }
  if (!Array.prototype.sortBy) Array.prototype.sortBy = sb;

  function sb(f){
    for (var i=this.length;i;){
      var o = this[--i];
      this[i] = [].concat(f.call(o,o,i),o);
    }
    this.sort(function(a,b){
      for (var i=0,len=a.length;i<len;++i){
        if (a[i]!=b[i]) return a[i]<b[i]?-1:1;
      }
      return 0;
    });
    for (var i=this.length;i;){
      this[--i]=this[i][this[i].length-1];
    }
    return this;
  }
})();
Puzzled Puffin

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