“Urutkan serangkaian objek JavaScript” Kode Jawaban

Urutkan serangkaian objek js

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0));
Fancy Finch

JavaScript mengurutkan array objek

// Price Low To High
array?.sort((a, b) => (a.price > b.price ? 1 : -1))
// Price High To Low
array?.sort((a, b) => (a.price > b.price ? -1 : 1))
// Name A to Z
array?.sort((a, b) => (a.name > b.name ? 1 : 1))
// Name Z to A
array?.sort((a, b) => (a.name > b.name ? -1 : 1))
// Sort by date
array.sort((a,b) =>  new Date(b.date) - new Date(a.date));
ashirbad-panigrahi

JavaScript Sorts Array dengan objek

var array = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "Jake", age: 25}
];

array.sort(function(a, b) {
  return a.age - b.age;
}); // Sort youngest first
TC5550

Urutkan serangkaian objek JavaScript

list.sort((a, b) => (a.color > b.color) ? 1 : -1)
Jittery Jaguar

Urutkan serangkaian objek JavaScript

var items = [
  { name: 'Edward', value: 21 },
  { name: 'Sharpe', value: 37 },
  { name: 'And', value: 45 },
  { name: 'The', value: -12 },
  { name: 'Magnetic', value: 13 },
  { name: 'Zeros', value: 37 }
];

// sort by value
items.sort(function (a, b) {
  return a.value - b.value;
});

// sort by name
items.sort(function(a, b) {
  var nameA = a.name.toUpperCase(); // ignore upper and lowercase
  var nameB = b.name.toUpperCase(); // ignore upper and lowercase
  if (nameA < nameB) {
    return -1;
  }
  if (nameA > nameB) {
    return 1;
  }

  // names must be equal
  return 0;
});
Clever Crocodile

Urutkan serangkaian objek JavaScript

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

books.sort((a, b) => a.name.localeCompare(b.name))
Ntiyiso-Rikhotso

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