“rgb ke hex python” Kode Jawaban

rgb ke hex python

from colormap import rgb2hex
from colormap import hex2rgb

print(rgb2hex(255, 255, 255))
print(hex2rgb('#FFFFFF'))

>>> #FFFFFF
>>> (255, 255, 255)
Mig

hex ke rgb python

def hex2rgb(color):
  hex = color.lstrip('#')
  rgb = tuple(int(hex[i:i+2], 16) for i in (0, 2, 4))
  
  return rgb

hex_color = "#B4FBB8"
rgb_color = hex2rgb(hex_color)

print(rgb_color)
#(180, 251, 184)
CodeHunter

python rgb ke hex

def RGBToHex(r, g, b):
  return '#%02X%02X%02X' % (r, g, b)
  
print(RGBToHex(255, 255, 255))
Frail Finch

hex ke rgb python

def hex_to_rgb(hex_string):
    """Fastest Solution Universe
    
    >>> hex_to_rgb("#abc")
        (170, 187, 204)
    >>> hex_to_rgb("#ABC")
        (170, 187, 204)
    >>> hex_to_rgb("#aabbcc")
        (170, 187, 204)
    >>> hex_to_rgb("abc")
        (170, 187, 204)
    >>> hex_to_rgb("ABC")
        (170, 187, 204)
    >>> hex_to_rgb("aabbcc")
        (170, 187, 204)
    """
    str_len = len(hex_string)
    if hex_string.startswith("#"):
        if str_len == 7:
            r_hex = hex_string[1:3]
            g_hex = hex_string[3:5]
            b_hex = hex_string[5:7]
        elif str_len == 4:
            r_hex = hex_string[1:2] * 2
            g_hex = hex_string[2:3] * 2
            b_hex = hex_string[3:4] * 2
    elif str_len == 3:
        r_hex = hex_string[0:1] * 2
        g_hex = hex_string[1:2] * 2
        b_hex = hex_string[2:3] * 2
    else:
        r_hex = hex_string[0:2]
        g_hex = hex_string[2:4]
        b_hex = hex_string[4:6]

    return int(r_hex, 16), int(g_hex, 16), int(b_hex, 16)
Puzzled Puffin

hex ke rgb python

h = input('Enter hex: ').lstrip('#')
print('RGB =', tuple(int(h[i:i+2], 16) for i in (0, 2, 4)))
Ava

rgb ke hex python

import matplotlib

print(matplotlib.colors.to_hex([ 0.47, 0.0, 1.0 ]))
print(matplotlib.colors.to_hex([ 0.7, 0.321, 0.3, 0.5 ], keep_alpha=True))

print(matplotlib.colors.to_rgb("#aabbcc"))
print(matplotlib.colors.to_rgb("#ddee9f"))
Temerold

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