import datetime
# The size of each step in days
day_delta = datetime.timedelta(days=1)
start_date = datetime.date.today()
end_date = start_date + 7*day_delta
for i in range((end_date - start_date).days):
print(start_date + i*day_delta)
#this does not account for leap years
years = [str(i) for i in range(2010, 2022)]
months = ['01', '02', '03', '04', '05', '06',
'07', '08', '09', '10', '11', '12']
days = [31, 28 , 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
for i in range(len(years)):
for j in range(len(months)):
for k in range(1, days[j] + 1):
print("The date is: " + years[i] + months[j] + str(k))
# this DOES account for leap years
years = ['2023', '2024', '2028']
months = ['01', '02', '03', '04', '05', '06',
'07', '08', '09', '10', '11', '12']
days = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
for i in range(len(years)):
for j in range(len(months)):
if (((int(years[i]) % 4 == 0 and int(years[i]) % 100 != 0) or (int(years[i])% 400 == 0)) and months[j] == '02'):
for k in range(1, days[j] + 2):
print(years[i] + '-' + months[j] + '-' + str(k))
else:
for k in range(1, days[j] + 1):
print(years[i] + '-' + months[j] + '-' + str(k))
#2023-01-1
#2023-01-2
#2023-01-3
#...