“cara mengatur timeline propee di python” Kode Jawaban

cara mengatur timeline propee di python

event = data_set_adj['EnglishName']
begin = data_set_adj['Start']
end = data_set_adj['Finish']
length =  data_set_adj['Length']
dynasty = data_set_adj['Dynasty']
dynasty_col = data_set_adj['Dynasty_col']

dict_dynasty = dict(zip(dynasty.unique(), range(0,4*len(dynasty.unique()),4)))

levels = np.tile([-1.2,1.2, -0.8, 0.8, -0.4, 0.4],
                 int(np.ceil(len(begin)/6)))[:len(begin)]

import matplotlib.pyplot as plt
plt.style.use('ggplot')
plt.figure(figsize=(20,10))

for x in range(len(dynasty)):   
    plt.vlines(begin.iloc[x]+length.iloc[x]/2, dict_dynasty[dynasty.iloc[x]], dict_dynasty[dynasty.iloc[x]]+levels[x], color="tab:red")
    plt.barh(dict_dynasty[dynasty.iloc[x]], (end.iloc[x]-begin.iloc[x]), color=dynasty_col.iloc[x], height =0.3 ,left=begin.iloc[x], edgecolor = "black", alpha = 0.5)
    if x%2==0:
        plt.text(begin.iloc[x] + length.iloc[x]/2, 
                 dict_dynasty[dynasty.iloc[x]]+1.6*levels[x], event.iloc[x], 
                 ha='center', fontsize = '8')
    else:
        plt.text(begin.iloc[x] + length.iloc[x]/2, 
                 dict_dynasty[dynasty.iloc[x]]+1.25*levels[x], event.iloc[x], 
                 ha='center', fontsize = '8')
plt.tick_params(axis='both', which='major', labelsize=15)
plt.tick_params(axis='both', which='minor', labelsize=20)
plt.title('Chinese Dynasties', fontsize = '25')
plt.xlabel('Year', fontsize = '20')
ax = plt.gca()
ax.axes.yaxis.set_visible(False)
plt.xlim(900, 1915)
plt.ylim(-4,28)


plt.tight_layout()
plt.show()