“Python ke Php” Kode Jawaban

Python ke Php

import requests
import json
data = {
   "api_key": "PRIVATE_API_KEY",
   "profiles": [
       {
           "$consent": ["sms"],
           "phone_number": "+12345678900",
           "sms_consent": True
       }
   ]
}
headers = {
   "Content-Type": "application/json",
   "Cache-Control": "no-cache"
   }
conv = json.dumps(data)
response = requests.request("POST", "https://a.klaviyo.com/api/v2/list/{LIST_ID}/subscribe", data=conv, headers=headers)
print(response.text)
Sleepy Shark

Python ke Php

<?php echo "Hello" ?>
Sleepy Shark

Python ke Php

import requests
import json
data = {
   "api_key": "PRIVATE_API_KEY",
   "profiles": [
       {
           "$consent": ["sms"],
           "phone_number": "+12345678900",
           "sms_consent": True
       }
   ]
}
headers = {
   "Content-Type": "application/json",
   "Cache-Control": "no-cache"
   }
conv = json.dumps(data)
response = requests.request("POST", "https://a.klaviyo.com/api/v2/list/{LIST_ID}/subscribe", data=conv, headers=headers)
print(response.text)
Sleepy Shark

Python ke Php

def no_of_notes(amt, note):
    n = [0, 0, 0]
    min_amt = 0
    for i in note:
        min_amt += i

    if amt < min_amt:
        i = 0
        while amt != 0:
            n1 = amt // note[i]
            amt = amt - (n1 * note[i])
            n[i] += n1
            i += 1
    else:
        n = [1, 1, 1]
        if amt == min_amt:
            return n
        i = 0
        amt -= min_amt
        while amt != 0:
            n1 = amt // note[i]
            amt = amt - (n1 * note[i])
            n[i] += n1
            i += 1
    return n


Amount = int(input('Enter a price: '))
note = [500, 200, 100]
result = no_of_notes(Amount, note)
number_of_notes = 0

for i in range(len(note)):
    if result[i] != 0:
        print(f' Rs.{note[i]} notes = {result[i]}')
    number_of_notes += result[i]

print(f'Total number of notes = {number_of_notes}')
Sathish Suresh

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