PANDAS ILOC
import pandas as pd
d = [[1,2,3,4,5,6,7,8],["a","b","c","d","e","f","g","h"]
df = pd.DataFrame(d)
x = df.iloc[0,1]
print(x)
Jean Aoun
import pandas as pd
d = [[1,2,3,4,5,6,7,8],["a","b","c","d","e","f","g","h"]
df = pd.DataFrame(d)
x = df.iloc[0,1]
print(x)mydict = [{'a': 1, 'b': 2, 'c': 3, 'd': 4},
... {'a': 100, 'b': 200, 'c': 300, 'd': 400},
... {'a': 1000, 'b': 2000, 'c': 3000, 'd': 4000 }]
>>> df = pd.DataFrame(mydict)
>>> df
a b c d
0 1 2 3 4
1 100 200 300 400
2 1000 2000 3000 4000
>>>type(df.iloc[0])
<class 'pandas.core.series.Series'>
>>>df.iloc[0]
a 1
b 2
c 3
d 4
Name: 0, dtype: int64