“PD.Cut di Panda” Kode Jawaban

DataFrame Cut berdasarkan jangkauan

test = pd.DataFrame({'days': [0,20,30,31,45,60]})

test['range1'] = pd.cut(test.days, [0,30,60], include_lowest=True)
#30 value is in [30, 60) group
test['range2'] = pd.cut(test.days, [0,30,60], right=False)
#30 value is in (0, 30] group
test['range3'] = pd.cut(test.days, [0,30,60])
print (test)
   days          range1    range2    range3
0     0  (-0.001, 30.0]   [0, 30)       NaN
1    20  (-0.001, 30.0]   [0, 30)   (0, 30]
2    30  (-0.001, 30.0]  [30, 60)   (0, 30]
3    31    (30.0, 60.0]  [30, 60)  (30, 60]
4    45    (30.0, 60.0]  [30, 60)  (30, 60]
5    60    (30.0, 60.0]       NaN  (30, 60]
Gifted Gecko

PD.Cut di Panda

>>> pd.qcut(range(5), 3, labels=["good", "medium", "bad"])
... 
[good, good, medium, bad, bad]
Categories (3, object): [good < medium < bad]
Famous Flamingo

DataFrame Cut

import pandas as pd

#设置切分区域
listBins = [0, 10, 20, 30, 40, 50, 60, 1000000]

#设置切分后对应标签
listLabels = ['0_10','11_20','21_30','31_40','41_50','51_60','61及以上']

#利用pd.cut进行数据离散化切分
"""
pandas.cut(x,bins,right=True,labels=None,retbins=False,precision=3,include_lowest=False)
x:需要切分的数据
bins:切分区域
right : 是否包含右端点默认True，包含
labels:对应标签，用标记来代替返回的bins，若不在该序列中，则返回NaN
retbins:是否返回间距bins
precision:精度
include_lowest:是否包含左端点，默认False，不包含
"""
df['fenzu'] = pd.cut(df['data'], bins=listBins, labels=listLabels, include_lowest=True)
Red Team

Jawaban yang mirip dengan “PD.Cut di Panda”

Pertanyaan yang mirip dengan “PD.Cut di Panda”

Lebih banyak jawaban terkait untuk “PD.Cut di Panda” di Python

Jelajahi jawaban kode populer menurut bahasa

Jelajahi bahasa kode lainnya

Shell/Bash
C#
C++
C
CSS
HTML
Java
JavaScript
Objective-C
PHP
Python
Sql
Swift
Ruby
TypeScript
Go
Kotlin
Assembly
R
VBA
Scala
Rust
Dart
Elixir
Clojure
Haskell
Matlab
Erlang
Cobol
Fortran
Scheme
Perl
Groovy
Lua
Julia
Delphi
Abap
Lisp
Prolog
Pascal
ActionScript
Basic
Solidity
PowerShell
GDScript
Excel