“PHP MySQL menyiapkan pernyataan” Kode Jawaban

SQL repare php

$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

$conn = new mysqli($servername, $username, $password, $dbname);

if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}

$stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname, email) VALUES (?, ?, ?)");
$stmt->bind_param("sss", $firstname, $lastname, $email);

$firstname = "John";
$lastname = "Doe";
$email = "[email protected]";
$stmt->execute();

echo "New records created successfully";

$stmt->close();
$conn->close();
Realy Silly Shark

php mysql menyiapkan kueri

$stmt = $mysqli->prepare("SELECT * FROM myTable WHERE name = ? AND age = ?");
$stmt->bind_param("si", $_POST['name'], $_POST['age']);
$stmt->execute();
$stmt->close();
Sal-versij

PHP MySQL menyiapkan pernyataan

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);

// Check connection
if ($conn->connect_error) {
  die("Connection failed: " . $conn->connect_error);
}

// prepare and bind
$stmt = $conn->prepare("INSERT INTO MyGuests (firstname, lastname, email) VALUES (?, ?, ?)");
$stmt->bind_param("sss", $firstname, $lastname, $email);

// set parameters and execute
$firstname = "John";
$lastname = "Doe";
$email = "[email protected]";
$stmt->execute();

$firstname = "Mary";
$lastname = "Moe";
$email = "[email protected]";
$stmt->execute();

$firstname = "Julie";
$lastname = "Dooley";
$email = "[email protected]";
$stmt->execute();

echo "New records created successfully";

$stmt->close();
$conn->close();
?>
naly moslih

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