Lengkapi permintaan AJAX JQuery PHP Call | Permintaan AJAX
<script type="text/javascript">
function ajaxCall(formID, showID) {
var form = $('#' + formID);
$.ajax({
type: form.attr('method'),
url: form.attr('action'),
data: form.serialize(),
dataType: "JSON",
cache: false,
success: function (data, status, xhr) {
$('#' + showID).html('').fadeOut('fast');
$('#' + showID).html(data).fadeIn('slow');
},
error: function (xhr, status, error) {
//alert(xhr);
console.error(xhr);
}
});
}
</script>
Amin Arjmand
