javascript membandingkan array objek hanya menyimpan entri tidak di keduanya

var result = result1.filter(function (o1) {
    return result2.some(function (o2) {
        return o1.id === o2.id; // return the ones with equal id
   });
});
// if you want to be more clever to find those in common:
let result = result1.filter(o1 => result2.some(o2 => o1.id === o2.id));

// To find those in 1 NOT in 2:
let result = result1.filter(o1 => !result2.some(o2 => o1.id === o2.id));
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