“JavaScript membandingkan array” Kode Jawaban

JavaScript membandingkan array

Array.prototype.equals = function(arr2) {
  return (
    this.length === arr2.length &&
    this.every((value, index) => value === arr2[index])
  );
};

[1, 2, 3].equals([1, 2, 3]);	// true
[1, 2, 3].equals([3, 6, 4, 2]);	// false
garzj

Cara membandingkan array di JS

// THE PROBLEM:
const firstArray = ["cookies", "milk", "chocolate"]
const secondArray = ["cookies", "milk", "chocolate"]
console.log(firstArray == secondArray) // always returns FALSE

// THE SOLUTION:
if(JSON.stringify(firstArray) === JSON.stringify(secondArray)){
  console.log("firstArray is the same as the secondArray")
} else {
  console.log("firstArray is different from the secondArray")
}
Disgusted Dunlin

cara membandingkan dua array javascript

function arraysAreIdentical(arr1, arr2){
    if (arr1.length !== arr2.length) return false;
    for (var i = 0, len = arr1.length; i < len; i++){
        if (arr1[i] !== arr2[i]){
            return false;
        }
    }
    return true; 
}
Spotless Shrew

Bandingkan dua array dalam JavaScript

let arr1 = [1, 4, 7, 4, 2, 3];
let arr2 = [1, 2, 3, 4, 7, 18];

const is_same = arr1.length == arr2.length &&
  (arr1.every((currElem)=>{
    if(arr2.indexOf(currElem)> -1){
      return (currElem == arr2[arr2.indexOf(currElem)]);
    }return false
  })
)
console.log(is_same)
Gentle Gerenuk

membandingkan dua array dalam javascript

const arr1 = [1, 2, 3];
const arr2 = [1, 3, 3];

if (arr1.length !== arr2.length) return console.log("false");
for (let i = 0; i < arr1.length; i++) {
    for (let j = 0; j < arr2.length; j++) {
        if (arr1[i] === arr2[j]) {
            console.log("yes match", arr1[i], arr2[j]);
            continue;
        }
        console.log("no match", arr1[i], arr2[j]);
    }
}
abhi

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