ES6 Bandingkan dua array
let difference = arrA.filter(x => !arrB.includes(x));
Adventurous Ant
let difference = arrA.filter(x => !arrB.includes(x));function diffArray(arr1, arr2) {
return arr1
.concat(arr2)
.filter(item => !arr1.includes(item) || !arr2.includes(item));
}Array.prototype.equals = function(arr2) {
return (
this.length === arr2.length &&
this.every((value, index) => value === arr2[index])
);
};
[1, 2, 3].equals([1, 2, 3]); // true
[1, 2, 3].equals([3, 6, 4, 2]); // false// THE PROBLEM:
const firstArray = ["cookies", "milk", "chocolate"]
const secondArray = ["cookies", "milk", "chocolate"]
console.log(firstArray == secondArray) // always returns FALSE
// THE SOLUTION:
if(JSON.stringify(firstArray) === JSON.stringify(secondArray)){
console.log("firstArray is the same as the secondArray")
} else {
console.log("firstArray is different from the secondArray")
}const isEqual = (a, b) => JSON.stringify(a) === JSON.stringify(b);
// Examples
isEqual([1, 2, 3], [1, 2, 3]); // true
isEqual([1, 2, 3], [1, '2', 3]); // falsefunction arraysAreIdentical(arr1, arr2){
if (arr1.length !== arr2.length) return false;
for (var i = 0, len = arr1.length; i < len; i++){
if (arr1[i] !== arr2[i]){
return false;
}
}
return true;
}