// For large data, it's better to use reduce. Supose arr has a large data in this case:
const arr = [1, 5, 3, 5, 2];
const max = arr.reduce((a, b) => { return Math.max(a, b) });
// For arrays with relatively few elements you can use apply:
const max = Math.max.apply(null, arr);
// or spread operator:
const max = Math.max(...arr);
var numbers = [1, 2, 3, 4];
Math.max(...numbers) // 4
Math.min(...numbers) // 1function findHighestNumber(nums) {
let inputs = nums.filter((val, i) => nums.indexOf(val) === i)
let max = Math.max(...nums);
let min = Math.min(...nums);
return max + (-min);
}
console.log(difference([1, 7, 18, -1, -2, 9]));function minMax(arr) {
return [Math.min(...arr), Math.max(...arr)];
}const array1 = [1, 3, 2];
console.log(Math.max(...array1));int max;
max=INT_MIN;
for(int i=0;i<ar.length();i++){
if(ar[i]>max){
max=ar[i];
}