“Menyortir array objek di JS” Kode Jawaban

Urutkan serangkaian objek js

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

books.sort((a,b) => (a.name > b.name) ? 1 : ((b.name > a.name) ? -1 : 0));
Fancy Finch

JavaScript Sorts Array dengan objek

var array = [
  {name: "John", age: 34},
  {name: "Peter", age: 54},
  {name: "Jake", age: 25}
];

array.sort(function(a, b) {
  return a.age - b.age;
}); // Sort youngest first
TC5550

Urutkan serangkaian objek JavaScript

list.sort((a, b) => (a.color > b.color) ? 1 : -1)
Jittery Jaguar

JavaScript mengurutkan objek berdasarkan kunci

function sortObjectByKeys(o) {
    return Object.keys(o).sort().reduce((r, k) => (r[k] = o[k], r), {});
}
var unsorted = {"c":"crane","b":"boy","a":"ant"};
var sorted=sortObjectByKeys(unsorted); //{a: "ant", b: "boy", c: "crane"}
Grepper

Urutkan serangkaian objek JavaScript

const books = [
  {id: 1, name: 'The Lord of the Rings'},
  {id: 2, name: 'A Tale of Two Cities'},
  {id: 3, name: 'Don Quixote'},
  {id: 4, name: 'The Hobbit'}
]

books.sort((a, b) => a.name.localeCompare(b.name))
Ntiyiso-Rikhotso

Menyortir array objek di JS

function compare( a, b ) {
  if ( a.last_nom < b.last_nom ){
    return -1;
  }
  if ( a.last_nom > b.last_nom ){
    return 1;
  }
  return 0;
}

objs.sort( compare );
Fragile Finch

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