Menggunakan filter dan pipa di RXJS
const ob$: Observable<number> = of(1, 2, 3, 4, 5, 6, 7, 8, 9, 10).pipe(filter( v => v % 2 === 0), map( v => v * 10));
Puzzled Pollan
const ob$: Observable<number> = of(1, 2, 3, 4, 5, 6, 7, 8, 9, 10).pipe(filter( v => v % 2 === 0), map( v => v * 10));