Hasil agregat dari model linier berjalan R

Karena pemodelan regresi seringkali lebih "seni" daripada sains, saya sering menemukan diri saya menguji banyak iterasi dari struktur regresi. Apa saja cara efisien untuk meringkas informasi dari berbagai model ini dalam upaya menemukan model "terbaik"? Salah satu pendekatan yang saya gunakan adalah memasukkan semua model ke dalam daftar dan berjalan summary()melintasi daftar itu, tetapi saya membayangkan ada cara yang lebih efisien untuk membandingkan?

Kode & model sampel:

ctl <- c(4.17,5.58,5.18,6.11,4.50,4.61,5.17,4.53,5.33,5.14)
trt <- c(4.81,4.17,4.41,3.59,5.87,3.83,6.03,4.89,4.32,4.69)
group <- gl(2,10,20, labels=c("Ctl","Trt"))
weight <- c(ctl, trt)

lm1 <- lm(weight ~ group)
lm2 <- lm(weight ~ group - 1)
lm3 <- lm(log(weight) ~ group - 1)

#Draw comparisions between models 1 - 3?

models <- list(lm1, lm2, lm3)

lapply(models, summary)

Plot mereka!

http://svn.cluelessresearch.com/tables2graphs/longley.png

Atau, jika Anda harus, gunakan tabel: Paket apsrtable atau mtablefungsi dalam paket memisc .

Menggunakan mtable

 mtable123 <- mtable("Model 1"=lm1,"Model 2"=lm2,"Model 3"=lm3,
     summary.stats=c("sigma","R-squared","F","p","N"))

> mtable123

Calls:
Model 1: lm(formula = weight ~ group)
Model 2: lm(formula = weight ~ group - 1)
Model 3: lm(formula = log(weight) ~ group - 1)

=============================================
                 Model 1   Model 2   Model 3 
---------------------------------------------
(Intercept)      5.032***                    
                (0.220)                      
group: Trt/Ctl  -0.371                       
                (0.311)                      
group: Ctl                 5.032***  1.610***
                          (0.220)   (0.045)  
group: Trt                 4.661***  1.527***
                          (0.220)   (0.045)  
---------------------------------------------
sigma             0.696      0.696     0.143 
R-squared         0.073      0.982     0.993 
F                 1.419    485.051  1200.388 
p                 0.249      0.000     0.000 
N                20         20        20     
=============================================

Berikut ini tidak menjawab pertanyaan dengan tepat. Ini mungkin memberi Anda beberapa ide. Ini sesuatu yang baru-baru ini saya lakukan untuk menilai kecocokan beberapa model regresi menggunakan satu hingga empat variabel independen (variabel dependen ada di kolom pertama dari kerangka data df1).

# create the combinations of the 4 independent variables
library(foreach)
xcomb <- foreach(i=1:4, .combine=c) %do% {combn(names(df1)[-1], i, simplify=FALSE) }

# create formulas
formlist <- lapply(xcomb, function(l) formula(paste(names(df1)[1], paste(l, collapse="+"), sep="~")))

Isi as.character (formlist) tadinya

 [1] "price ~ sqft"                     "price ~ age"                     
 [3] "price ~ feats"                    "price ~ tax"                     
 [5] "price ~ sqft + age"               "price ~ sqft + feats"            
 [7] "price ~ sqft + tax"               "price ~ age + feats"             
 [9] "price ~ age + tax"                "price ~ feats + tax"             
[11] "price ~ sqft + age + feats"       "price ~ sqft + age + tax"        
[13] "price ~ sqft + feats + tax"       "price ~ age + feats + tax"       
[15] "price ~ sqft + age + feats + tax"

Kemudian saya mengumpulkan beberapa indeks yang bermanfaat

# R squared
models.r.sq <- sapply(formlist, function(i) summary(lm(i))$r.squared)
# adjusted R squared
models.adj.r.sq <- sapply(formlist, function(i) summary(lm(i))$adj.r.squared)
# MSEp
models.MSEp <- sapply(formlist, function(i) anova(lm(i))['Mean Sq']['Residuals',])

# Full model MSE
MSE <- anova(lm(formlist[[length(formlist)]]))['Mean Sq']['Residuals',]

# Mallow's Cp
models.Cp <- sapply(formlist, function(i) {
SSEp <- anova(lm(i))['Sum Sq']['Residuals',]
mod.mat <- model.matrix(lm(i))
n <- dim(mod.mat)[1]
p <- dim(mod.mat)[2]
c(p,SSEp / MSE - (n - 2*p))
})

df.model.eval <- data.frame(model=as.character(formlist), p=models.Cp[1,],
r.sq=models.r.sq, adj.r.sq=models.adj.r.sq, MSEp=models.MSEp, Cp=models.Cp[2,])

Kerangka data terakhir adalah

                      model p       r.sq   adj.r.sq      MSEp         Cp
1                price~sqft 2 0.71390776 0.71139818  42044.46  49.260620
2                 price~age 2 0.02847477 0.01352823 162541.84 292.462049
3               price~feats 2 0.17858447 0.17137907 120716.21 351.004441
4                 price~tax 2 0.76641940 0.76417343  35035.94  20.591913
5            price~sqft+age 3 0.80348960 0.79734865  33391.05  10.899307
6          price~sqft+feats 3 0.72245824 0.71754599  41148.82  46.441002
7            price~sqft+tax 3 0.79837622 0.79446120  30536.19   5.819766
8           price~age+feats 3 0.16146638 0.13526220 142483.62 245.803026
9             price~age+tax 3 0.77886989 0.77173666  37884.71  20.026075
10          price~feats+tax 3 0.76941242 0.76493500  34922.80  21.021060
11     price~sqft+age+feats 4 0.80454221 0.79523470  33739.36  12.514175
12       price~sqft+age+tax 4 0.82977846 0.82140691  29640.97   3.832692
13     price~sqft+feats+tax 4 0.80068220 0.79481991  30482.90   6.609502
14      price~age+feats+tax 4 0.79186713 0.78163109  36242.54  17.381201
15 price~sqft+age+feats+tax 5 0.83210849 0.82091573  29722.50   5.000000

Akhirnya, plot Cp (menggunakan library wle)