“compactmap” Kode Jawaban

compactmap

///lets say we have array of string which contains Int value but we are not sure about that
///all the elements can convert into int because we some element can't be int


var array = ["3", "data", "2", "5", "23", "hello"]


var simpleMapResult: [Int?] = array.map { elment in
    return Int(elment)
}
print("The original array => ")
print(array)
print("\nAfter maping through we'll see the result is option int array =>")
print(simpleMapResult)

///Next task is make them no-optional and remove nil

var simpleMapRemovedNil: [Int?] = simpleMapResult.filter { element in
    return element != nil
}
print("\nNow we have array of int which does not have nil value")
print(simpleMapRemovedNil)

//Now make them non-optional

var simpleMapNonOptional: [Int] = simpleMapRemovedNil.map { element in
    return element!
}

print("\nNow we have array of non-optional int")
print(simpleMapNonOptional)


/// not the simple approch is compactMap

var compactMapNonOptional: [Int] = array.compactMap { elment in
    return Int(elment)
}
print("\nCompact map output")
print(compactMapNonOptional)



/* Output is
The original array => 
["3", "data", "2", "5", "23", "hello"]

After maping through we'll see the result is option int array =>
[Optional(3), nil, Optional(2), Optional(5), Optional(23), nil]

Now we have array of int which does not have nil value
[Optional(3), Optional(2), Optional(5), Optional(23)]

Now we have array of non-optional int
[3, 2, 5, 23]

Compact map output
[3, 2, 5, 23]
*/