Jika tidak na di r
which( !is.na(p), arr.ind=TRUE)
MF
which( !is.na(p), arr.ind=TRUE)lapply(apply(p, 1, function(x) which(!is.na(x)) ) , paste, collapse=", ")> which( !is.na(p), arr.ind=TRUE)
row col
[1,] 1 2
[2,] 1 3
[3,] 2 4
[4,] 4 5
[5,] 2 7> apply(p, 1, function(x) which(!is.na(x)) )
[[1]]
[1] 2 3
[[2]]
[1] 4 7
[[3]]
integer(0)
[[4]]
[1] 5
[[5]]
integer(0)