“Python Regex” Kode Jawaban

Python Regex Tester

Find below are online regex tester

https://regex101.com/
https://pythex.org/
http://www.pyregex.com/
https://www.debuggex.com/
  
Here you insert your regular expression and get the test result.
Thank you !!!
Ankur

Pola dalam Python

rows = 6                        #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()
tymepas

Python Regex

import re

# Regex Cheat sheet : https://www.dataquest.io/blog/regex-cheatsheet/
# Regex python tester : https://pythex.org/
# re doc : https://docs.python.org/3/library/re.html

text = "i like train" 
reg = r"[a-c]" #the group of char a to c

if re.match(reg, text): #Check if regex is correct
	print(text)
else:
  print("Not any match")
Nervous Nightingale

Kompilasi Python Re

import re
#	Compile a regular expression pattern into a regular expression object, which can be used for matching using its match(), search() and other methods, described below.

prog = re.compile(pattern)
result = prog.match(string)

#	is equivalent to

result = re.match(pattern, string)
Blushing Barracuda

Python Regex

import re
>>> m = re.search('(?<=abc)def', 'abcdef')
>>> m.group(0)
'def'
Proud Penguin

Python Regex

# Recursive Python3 program to find if a given pattern is
# present in a text
 
def exactMatch(text, pat, text_index, pat_index):
    if text_index == len(text) and pat_index != len(pat):
        return 0
  
    # Else If last character of pattern reaches
    if pat_index == len(pat):
        return 1
  
    if text[text_index] == pat[pat_index]:
        return exactMatch(text, pat, text_index+1, pat_index+1)
  
    return 0
 
  
# This function returns true if 'text' contain 'pat'
def contains(text, pat, text_index, pat_index):
    # If last character of text reaches
    if text_index == len(text):
        return 0
  
    # If current characters of pat and text match
    if text[text_index] == pat[pat_index]:
        if exactMatch(text, pat, text_index, pat_index):
            return 1
        else:
            return contains(text, pat, text_index+1, pat_index)
  
    # If current characters of pat and tex don't match
    return contains(text , pat, text_index+1, pat_index)
  
# Driver program to test the above function
 
print(contains("geeksforgeeks", "geeks", 0, 0))
print(contains("geeksforgeeks", "geeksquiz", 0, 0))
print(contains("geeksquizgeeksquiz", "quiz", 0, 0))
 
# This code is contributed by ankush_953.
samuel karanja

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