periksa apakah argv ada python
# First, make sure that you import "sys"
import sys
# Next, run a simple conditonal statement to check if argv exists
if len(sys.argv) > 1:
result = sys.argv[1]
else:
result = False
# Finally, you can use the result from the above test and run further code accordingly
if result == False:
print("argv DOES NOT exist!")
else:
print("argv exists!")
if result == "foo":
# some code here, which executes when argv is "foo"
print("Foo!")
elif result == "bar":
# some code here, which executes when argv is "bar"
print("Bar")
else:
# some code here, which executes as the default, if the argument value is niether "foo", nor "bar"
print("Baz")
# Happy coding, my homies <3
CoderHomie