Labu bersyarat menurut urrl
from flask import Flask
from flask import request
from flask import render_template
app = Flask(__name__)
@app.route('/')
def show_index():
return render_template('funding.html')
@app.route('/funding')
def show_funding():
return render_template('funding.html')
if __name__ == '__main__':
app.run(debug = True)
Defeated Dogfish