“Howmanydays Python” Kode Jawaban

Howmanydays Python

# python program Find number of
# times every day occurs in a Year
  
 
import datetime
import calendar
  
def day_occur_time(year):
     
    # stores days in a week
    days = [ "Monday", "Tuesday", "Wednesday", 
           "Thursday",  "Friday", "Saturday",
           "Sunday" ]
     
    # Initialize all counts as 52
    L = [52 for i in range(7)]
     
    # Find the index of the first day
    # of the year
    pos = -1
    day = datetime.datetime(year, month = 1, day = 1).strftime("%A")
    for i in range(7):
        if day == days[i]:
            pos = i
             
    # mark the occurrence to be 53 of 1st day
    # and 2nd day if the year is leap year
    if calendar.isleap(year):
        L[pos] += 1
        L[(pos+1)%7] += 1
         
    else:
        L[pos] += 1
         
     
    # Print the days
    for i in range(7):
        print(days[i], L[i])
      
  
# Driver Code
year = 2019
day_occur_time(year)