from math import sqrt
for i in range(2, int(sqrt(num)) + 1):
if num % i == 0:
print("Not Prime")
break
print("Prime")
# Note: Use this if your num is big (ex. 10000 or bigger) for efficiency
# The result is still the same if the num is smallera=int(input('print number:'))
for i in range(2,a):
if a%i !=0:
continue
else:
print("Its not a prime number")
break # here break is exicuted then it means else would not be exicuted.
else:
print("Its a prime number")#prime number verification program
a=int(input('print number:'))
for i in range(2,a):
if a%i !=0:
continue
else:
print("Its not a prime number")
break # here break is exicuted then it means else would not be exicuted.
else:
print("Its a prime number")#this is out of the for loop suite.
# This shows how we can use for + else using a break in between
for x in range(1,101):
# if you want to find whether a user input is a prime number
# use the following insted of the first for loop
# x = int(input("Type a number: "))
for i in range(2, x):
if x % i == 0:
print(x, "is not a prime number.")
break
else:
print(x, "is a prime number.")
# This will print all the numbers from 1-100,
# in the same line will print whether it is a prime or not
# if you use the user input method
# when you type 9, the output will be:
# 9 is not a prime number.
# when you type 7, the output will be:
# 7 is a prime number.def prime(n):
if n>1:
if n==2 or n==3:
print("it is a prime number")
for i in range(2,int(n/2)+1):
if n%i==0:
print("it is not a prime number")
break
else:
print("it's a prime number")
break
else:
print("it is not a prime number")
a=int(input('number:'))
if a % 2 ==0 and a / 2 <= 2:
print('composite')
elif a % 3 == 0 and a/3 <= 2:
print('composit')
elif a % 5 == 0 and a/5 <= 2 :
print('composit')
elif a % 7 == 0 and a/7 <= 2:
print('composit')
else:
print('prime')
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