“*kwargs” Kode Jawaban

*kwargs

# Python program to illustrate 
# *kwargs for variable number of keyword arguments
 
def myFun(**kwargs):
    for key, value in kwargs.items():
        print ("%s == %s" %(key, value))
 
# Driver code
myFun(first ='Geeks', mid ='for', last='Geeks') 

''' output: 
last == Geeks
mid == for
first == Geeks
'''