“JavaScript Hapus objek duplikat dari Array ES6” Kode Jawaban

cara menghapus objek array duplikat di javascript

const arr = [{id: 1, name: 'one'}, {id: 2, name: 'two'}, {id: 1, name: 'one'}]

const ids = arr.map(o => o.id)
const filtered = arr.filter(({id}, index) => !ids.includes(id, index + 1))

console.log(filtered)
DecodeBuzzing

Hapus duplikat dari array objek JavaScript

let arr = [{name: "john"}, {name: "jane"}, {name: "imelda"}, {name: "john"}];

const uniqueArray = arr.filter((v,i,a)=>a.findIndex(t=>(t.name===v.name))===i)
console.log(uniqueArray);
Light Lobster

Hapus objek duplikat dari array javascript

const addresses = [...]; // Some array I got from async call

const uniqueAddresses = Array.from(new Set(addresses.map(a => a.id)))
 .map(id => {
   return addresses.find(a => a.id === id)
 })
Ornate Rock Dragon

cara menghapus objek array duplikat di javascript

let days = ["senin","senin","selasa","selasa","rabu","kamis", "rabu"];
let fullname = [{name: "john"}, {name: "jane"}, {name: "imelda"}, {name: "john"},{name: "jane"}];

// REMOVE DUPLICATE FOR ARRAY LITERAL
const arrOne = new Set(days);
console.log(arrOne);

const arrTwo = days.filter((item, index) => days.indexOf(item) == index);
console.log(arrTwo);


// REMOVE DUPLICATE FOR ARRAY OBJECT
const arrObjOne = [...new Map(person.map(item => [JSON.stringify(item), item])).values()];
console.log(arrObjOne);

const arrObjTwo = Array.from(new Set(person.map(JSON.stringify))).map(JSON.parse);
console.log(arrObjTwo);
Restu Wahyu Saputra

cara menghapus objek array duplikat di javascript

let person = [
{name: "john"}, 
{name: "jane"}, 
{name: "imelda"}, 
{name: "john"},
{name: "jane"}
];

const obj = [...new Map(person.map(item => [JSON.stringify(item), item])).values()];
console.log(obj);
Restu Wahyu Saputra

JavaScript Hapus objek duplikat dari Array ES6

const
    listOfTags = [{ id: 1, label: "Hello", color: "red", sorting: 0 }, { id: 2, label: "World", color: "green", sorting: 1 }, { id: 3, label: "Hello", color: "blue", sorting: 4 }, { id: 4, label: "Sunshine", color: "yellow", sorting: 5 }, { id: 5, label: "Hello", color: "red", sorting: 6 }],
    keys = ['label', 'color'],
    filtered = listOfTags.filter(
        (s => o => 
            (k => !s.has(k) && s.add(k))
            (keys.map(k => o[k]).join('|'))
        )
        (new Set)
    );

console.log(filtered);
Amrit Khadka

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