“json.net Deserialize Dynamic” Kode Jawaban

json.net Deserialize Dynamic

dynamic d = JObject.Parse("{number:1000, str:'string', array: [1,2,3,4,5,6]}");

Console.WriteLine(d.number);
Console.WriteLine(d.str);
Console.WriteLine(d.array.Count);
Dante

Deserialize JSON ke Dynamic Object C#

dynamic obj = JsonConvert.DeserializeObject<ExpandoObject>(jsonObject, expConverter);
Poor Pollan

json.net Deserialize Dynamic


dynamic d = JObject.Parse("{number:1000, str:'string', array: [1,2,3,4,5,6]}");

Console.WriteLine(d.number);
Console.WriteLine(d.str);
Console.WriteLine(d.array.Count);

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