“tanda kurung seimbang” Kode Jawaban

tanda kurung seimbang

#include <iostream>
//This program works only for parantheses "()".
//Check more to get the program of balanced brackets.
using namespace std;

int is_balanced(char input[])
{
    char s[100];
    char last;
    int top = 0;
    
    
    for(int i = 0; input[i] != '\0'; i++)
    {
        if(input[i] == '(')
        {
            s[top] = '(';
            top++;
        }else if(input[i] == ')')
        {
            if(top == 0)
            {
                return 0;
            }
            
            top--;
            if(s[top] == ')')
            {
                return 0;
            }
        }
    }
    
    if(top == 0)
    {
        return 1;
    }else
    {
        return 0;
    }
    
}

int main()
{
    char input[100];
    cin >> input;
    if(is_balanced(input))
    {
        cout << "Balanced!\n";
    }else
    {
        cout << "Imbalanced!\n";
    }
    return 0;
}
rifatibn

Algoritma Periksa tanda kurung seimbang

if (null == str || ((str.length() % 2) != 0)) {
    return false;
} else {
    char[] ch = str.toCharArray();
    for (char c : ch) {
        if (!(c == '{' || c == '[' || c == '(' || c == '}' || c == ']' || c == ')')) {
            return false;
        }
    }
}
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