“Implementasi tumpukan” Kode Jawaban

Implementasi tumpukan

#include <iostream>
using namespace std;
int top = -1; //Globally defining the value of top as the stack is empty

    void push (int stack[ ] , int x , int n)
    {
        if ( top == n-1 )       //If the top position is the last of position of the stack, this means that the stack is full.
        {
            cout << "Stack is full.Overflow condition!" ;
        }
        else
        {
            top = top +1 ;            //Incrementing the top position 
            stack[ top ] = x ;       //Inserting an element on incremented position  
        }
    }
    bool isEmpty ( )
    {
        if ( top == -1 )  //Stack is empty
            return true ; 
        else
            return false;
    }
    void pop ( ) 
    {

        if( isEmpty ( ) )
        {
            cout << "Stack is empty. Underflow condition! " << endl ;
        }
        else    
        {
             top = top - 1 ; //Decrementing top’s position will detach last element from stack            
        }
    }
    int size ( )
    {
        return top + 1;
    }
    int topElement (int stack[])
    {
        return stack[ top ];
    }
    //Let's implement these functions on the stack given above 

    int main( )
    {
        int stack[ 3 ];
        // pushing element 5 in the stack .
        push(stack , 5 , 3 ) ;

        cout << "Current size of stack is " << size ( ) << endl ;

        push(stack , 10 , 3);
        push (stack , 24 , 3) ;

        cout << "Current size of stack is " << size( ) << endl ;

        //As the stack is full, further pushing will show an overflow condition.
        push(stack , 12 , 3) ;

        //Accessing the top element
        cout << "The current top element in stack is " << topElement(stack) << endl;

        //Removing all the elements from the stack
        for(int i = 0 ; i < 3;i++ )
            pop( );
        cout << "Current size of stack is " << size( ) << endl ;

        //As the stack is empty , further popping will show an underflow condition.
        pop ( );  

    }
Faithful Finch

bagaimana menerapkan tumpukan

#include<bits/stdc++.h>
using namespace std;
int Stack[100],n,top,i;

void push(int x) {
   if(top<n-1) {
   	  top++;
      Stack[top]=x; 
   } else {
      cout<<"Could not insert data, Stack is full.\n";
   }
}

int pop() {
	int data;
   if(top>-1) {
      data = Stack[top];
      top = top - 1;   
      return data;
   } else {
      cout<<"Could not retrieve data, Stack is empty.\n";
   }
}

void display()
{
    if(top>=0)
    {
        cout<<"\n The elements in STACK \n";
        for(i=top; i>=0; i--)
           cout<<Stack[i]<<" ";
    }
    else
    {
        cout<<"\n The STACK is empty";
    }
   
}

int main()
{
	cin>>n;
	top=-1;
	push(10);
	push(20);
	push(40);
	push(10);
	cout<<endl<<pop();
	display();
	return 0;
}
Motionless Mink

Jawaban yang mirip dengan “Implementasi tumpukan”

Pertanyaan yang mirip dengan “Implementasi tumpukan”

Lebih banyak jawaban terkait untuk “Implementasi tumpukan” di C++

Jelajahi jawaban kode populer menurut bahasa

Jelajahi bahasa kode lainnya