Cetak array di C
int array[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0};
int i;
for (i = 0; i < 10; i++) {
printf("%d ", array[i]);
}
Marton
int array[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0};
int i;
for (i = 0; i < 10; i++) {
printf("%d ", array[i]);
} for (int i = 0; i < length; i++)
{
printf("%d ", arr[i]);
} //Change "length" to size of your own array and rename "arr" to your own array name#include <stdio.h>
int main(void)
{
int size, i;
printf("Enter the size of the arrays:\n");
scanf("%d", &size);
int arr1[size];
printf("Enter the elements of the array:\n");
for (i = 0; i < size; i++) {
scanf_s("%d", arr1[size]);
}
printf("The current array is:\n %d", arr1[i]);
}#include <stdio.h>
int main() {
int array[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0};
int loop;
for(loop = 0; loop < 10; loop++)
printf("%d ", array[loop]);
return 0;
}