“Kode C ke Java Converter” Kode Jawaban

Kode C ke Java Converter

#include <stdio.h>
Tumbling Helmet

Kode C ke Java Converter

#include<stdio.h>
Prickly Pigeon

Kode C ke Java Converter

#include<stdio.h>
int main (void){
    int distance, d1;
   float fee;
    printf("Enter distance travelled:");scanf("%d", & distance),
    fees=0;
if(distance>=300){
        distance=distance-300;
        fee=20.00;
    if(distance> 208){
        d1=distance/200;
        fee-fee+2.00*d1;
        distance=distance-d1*200;
    Jif(distance>0){
        fee=fee+2.00;
Jelse if(distance>200){
       distance=distance-200;
       fee=2.00;
    if(distance>0){
        fee=fee+2.00;
Jelse(
   fee=2.00;)
printf("Fare=%.2f", fee);
return 0;
Freesergs Mercado

Kode C ke Java Converter

void prReplyException(char*errCode, char*errText)
{
  smne_reply_Error_def smneasnReply;
  short rc;
  char error_exception_code[50];
  char error_description[80];
  char logTxt[90];
  short chcnt=0;
  msgTxtDef
Akshay Patil

Kode C ke Java Converter

void rainbow_loop() {   //2

  idex++;
  ihue = ihue + 10;
  if (idex >= LED_COUNT/LED_FIZLINE) {
    idex = 0;
  }
  if (ihue > 255) {
    ihue = 0;
  }
  hsv_to_rgb(ihue*100, thissat, 255, leds[idex]);
  LEDSshow();
}
Foolish Fish

Kode C ke Java Converter

void main()
{
int a,b,c=1;
scanf("%d",&a);
printf("%d! = ",a);
for (b=a;b>0;b--){
    printf("%d * ",b);
    c=c*b;
}
printf("\n = %d",c);

}
Lovely Lizard

Kode C ke Java Converter

#include<stdio.h> #include<stdlib.h> #include<unistd.h>
void main(int argc,char *arg[])
{
printf("%d",argc); argv[0]="/bin/ls"; int pid; pid=fork(); if(pid<0)
{
printf("fork failed"); exit(1);
}
else if(pid==0)
{
execve( argv[0],argv,NULL);
}
else
{
printf("\n Process id is -%d\n",getpid()); wait(NULL);
exit(0);
} }
AMEER HAMZA NAWAZ

Kode C ke Java Converter


#include <iostream>
#include <stdio.h>
#include <string.h>
#include <math.h>
using namespace std;
 
int main(){
    int i;
    double l,sum;
    char s[31];
    while(gets(s)&&strcmp(s,"0") != 0)
    {
       l=strlen(s);
       sum=0;
       for(i=0;i<strlen(s);i++,l--)
          sum=sum+(s[i]-'0')*(pow(2,l)-1);
       cout<<int(sum)<<endl;
    }    
    return 0;
}
Badhon chowdhury

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