Syzygy Jam Tangan

16

(Terima kasih banyak kepada El'endia Starman dan Sp3000 karena membantu saya merancang kasus uji untuk ini!)

Diberi bilangan bulat positif ndan daftar periode rotasi bilangan bulat positif untuk sejumlah jarum jam (dalam detik), menghasilkan bilangan bulat positif terkecil di xmana xdetik setelah memulai jam dengan semua tangan selaras, tepat npada tangan yang selaras. Mereka tidak harus disejajarkan pada posisi awal - posisi apa pun baik-baik saja, asalkan xbilangan bulat dan diminimalkan. Selain itu, tidak semua tangan harus disejajarkan pada posisi yang sama - karena n=4, solusi di mana 2 kelompok 2 tangan disejajarkan adalah valid. Grup harus berukuran 2 atau lebih besar - dua tangan yang tidak selaras bukan merupakan 2 kelompok dari 1 tangan yang selaras, dan karenanya bukan solusi yang valid.

Anda dapat berasumsi bahwa hanya input yang memungkinkan untuk memiliki posisi ntangan yang tepat setelah jumlah integer detik akan diberikan - 2, [3,3,3]bukan input yang valid, karena setelah beberapa detik, ketiga tangan akan disejajarkan, sehingga tidak mungkin untuk mendapatkan tepat 2 selaras.

Contoh:

2, [3,4] -> 12
(the only option is a multiple of 12, so we pick 12 - 4 and 3 full rotations, respectively)

3, [3,5,6,9,29] -> 18
(picking 3, 6, and 9, the hands would align after 6, 3, and 2 rotations, respectively)

2, [1,1,4,5,10] -> 1
(picking 1 and 1 - note that 0 is not a valid answer because it is not a positive integer)

3, [2,2,6,7,11] -> 3
(picking 2, 2, and 6 - the 2s would be halfway through their second revolution, and the 6 would be halfway through its first revolution)

2, [2,7,5,3,3] -> 1
(picking 3 and 3, they are always aligned, so 1 is the minimum)

5, [4, 14, 36, 50, 63, 180, 210] -> 45
(after 45 seconds, the first, third, and sixth are aligned, as well as the second and seventh, for a total of 5)

Data uji:

7, [10, 22, 7, 6, 12, 21, 19] -> 87780
6, [25, 6, 2, 19, 11, 12] -> 62700
6, [23, 1, 8, 10, 9, 25] -> 41400
7, [6, 4, 1, 8, 10, 24, 23] -> 920
3, [18, 5, 23, 20, 21] -> 180
5, [10, 8, 14, 17, 5, 9] -> 2520
6, [1, 18, 12, 9, 8, 10, 23] -> 360
6, [12, 11, 6, 23, 25, 18, 13] -> 118404
4, [18, 11, 2, 9, 12, 8, 3] -> 8
7, [18, 25, 9, 13, 3, 5, 20] -> 11700
2, [17, 20, 15, 8, 23, 3] -> 15
3, [16, 3, 24, 13, 15, 2] -> 24
5, [7, 23, 24, 8, 21] -> 1932
6, [16, 10, 12, 24, 18, 2, 21] -> 720
6, [1, 17, 16, 13, 19, 4, 15] -> 53040
2, [3, 4, 20] -> 5
3, [9, 4, 16, 14, 1, 21] -> 16
5, [5, 17, 10, 20, 12, 11] -> 330
2, [21, 5, 22, 18] -> 90
4, [7, 25, 2, 8, 13, 24] -> 84
4, [13, 19, 2, 20, 7, 3] -> 420
5, [4, 14, 36, 50, 63, 180, 210] -> 45
5, [43, 69, 16, 7, 13, 57, 21] -> 27664
3, [22, 46, 92, 43, 89, 12] -> 276
4, [42, 3, 49, 88, 63, 81] -> 882
6, [2, 4, 7, 10, 20, 21, 52, 260] -> 65
6, [2, 3, 4, 7, 10, 20, 21, 52, 260] -> 35
2, [3, 4] -> 12
3, [3, 5, 6, 9, 29] -> 18
2, [1, 1, 4, 5, 10] -> 1
3, [2, 2, 6, 7, 11] -> 3
3, [41, 13, 31, 35, 11] -> 4433
3, [27, 15, 37, 44, 20, 38] -> 540
5, [36, 11, 14, 32, 44] -> 22176
3, [171, 1615, 3420] -> 3060
3, [46, 36, 12, 42, 28, 3, 26, 40] -> 36
5, [36, 25, 20, 49, 10, 27, 38, 42] -> 1350
4, [40, 28, 34, 36, 42, 25] -> 2142
5, [24, 26, 47, 22, 6, 17, 39, 5, 37, 32] -> 1248
4, [9, 27, 12, 6, 44, 10] -> 108

Aturan:

  • Celah standar dilarang
  • Ini kode-golf , jadi kode terpendek menang!

Papan peringkat

Cuplikan Stack di bagian bawah posting ini menghasilkan leaderboard dari jawaban a) sebagai daftar solusi terpendek per bahasa dan b) sebagai leaderboard keseluruhan.

Untuk memastikan bahwa jawaban Anda muncul, silakan mulai jawaban Anda dengan tajuk utama, menggunakan templat Penurunan harga berikut:

## Language Name, N bytes

di mana Nukuran kiriman Anda. Jika Anda meningkatkan skor Anda, Anda bisa menyimpan skor lama di headline, dengan mencoretnya. Contohnya:

## Ruby, <s>104</s> <s>101</s> 96 bytes

Jika Anda ingin memasukkan beberapa angka dalam tajuk Anda (mis. Karena skor Anda adalah jumlah dari dua file atau Anda ingin membuat daftar hukuman penterjemah secara terpisah), pastikan bahwa skor sebenarnya adalah angka terakhir di tajuk:

## Perl, 43 + 2 (-p flag) = 45 bytes

Anda juga dapat membuat nama bahasa menjadi tautan yang kemudian akan muncul di cuplikan:

## [><>](http://esolangs.org/wiki/Fish), 121 bytes

Tampilkan cuplikan kode

code-golf math Mego
sumber
5
Wow, aku bahkan tidak tahu ini kata . Benar-benar kata yang luar biasa, memenangkan hangman, memenangkan scrabble!
Digital Trauma
@DigitalTrauma Semoga beruntung menemukan 3 Yubin.
SuperJedi224

Jawaban:

7

Pyth, 28 27 24 byte

fqs-hMrS.RR7%R1cLTQ8 1vz

Cobalah online di Pyth Compiler .

Bagaimana itu bekerja

fqs-hMrS.RR7%R1cLTQ8 1vz

                          (implicit) Save the input number in z (as string).
                          (implicit) Save the input list in Q.

f                         Find the first positive integer T such that:
               cLTQ         Compute T/α for each α in Q.
            %R1             Get the fractional part of each result.
        .RR7                Round each fractional part to 7 decimal digits.
       S                    Sort the resulting numbers.
      r            8        Perform run-length encoding.
    hM                      Get the lengths of the runs.
   -                 1      Discard runs of length 1.
  s                         Add the remaining runs.
 q                    vz    Check is the sum matches the input number.
                          If it does, break and return T.

Uji kasus

$ cat input
7\n[10, 22, 7, 6, 12, 21, 19]\n87780
6\n[25, 6, 2, 19, 11, 12]\n62700
6\n[23, 1, 8, 10, 9, 25]\n41400
7\n[6, 4, 1, 8, 10, 24, 23]\n920
3\n[18, 5, 23, 20, 21]\n180
5\n[10, 8, 14, 17, 5, 9]\n2520
6\n[1, 18, 12, 9, 8, 10, 23]\n360
6\n[12, 11, 6, 23, 25, 18, 13]\n118404
4\n[18, 11, 2, 9, 12, 8, 3]\n8
7\n[18, 25, 9, 13, 3, 5, 20]\n11700
2\n[17, 20, 15, 8, 23, 3]\n15
3\n[16, 3, 24, 13, 15, 2]\n24
5\n[7, 23, 24, 8, 21]\n1932
6\n[16, 10, 12, 24, 18, 2, 21]\n720
6\n[1, 17, 16, 13, 19, 4, 15]\n53040
2\n[3, 4, 20]\n5
3\n[9, 4, 16, 14, 1, 21]\n16
5\n[5, 17, 10, 20, 12, 11]\n330
2\n[21, 5, 22, 18]\n90
4\n[7, 25, 2, 8, 13, 24]\n84
4\n[13, 19, 2, 20, 7, 3]\n420
5\n[4, 14, 36, 50, 63, 180, 210]\n45
5\n[43, 69, 16, 7, 13, 57, 21]\n27664
3\n[22, 46, 92, 43, 89, 12]\n276
4\n[42, 3, 49, 88, 63, 81]\n882
6\n[2, 4, 7, 10, 20, 21, 52, 260]\n65
6\n[2, 3, 4, 7, 10, 20, 21, 52, 260]\n35
2\n[3, 4]\n12
3\n[3, 5, 6, 9, 29]\n18
2\n[1, 1, 4, 5, 10]\n1
3\n[2, 2, 6, 7, 11]\n3
3\n[41, 13, 31, 35, 11]\n4433
3\n[27, 15, 37, 44, 20, 38]\n540
5\n[36, 11, 14, 32, 44]\n22176
3\n[171, 1615, 3420]\n3060
3\n[46, 36, 12, 42, 28, 3, 26, 40]\n36
5\n[36, 25, 20, 49, 10, 27, 38, 42]\n1350
4\n[40, 28, 34, 36, 42, 25]\n2142
5\n[24, 26, 47, 22, 6, 17, 39, 5, 37, 32]\n1248
4\n[9, 27, 12, 6, 44, 10]\n108
$ while read -r; do echo -e "$REPLY" | pyth -c 'qvwfqs-hMrS.RR7%R1cLTQ8 1vz'; done < input
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
True
Dennis
sumber
3

Jelly , 19 16 byte

P:×ⱮP%PĠẈḟ1Sʋ€iƓ

Mengambil array sebagai argumen, integer dari STDIN.

Terlalu lambat dan haus akan memori untuk sebagian besar kasus uji.

Cobalah online!

Versi alternatif, 14 byte

P÷€%1ĠẈḟ1Sʋ€iƓ

Ini berfungsi secara teori, tetapi mungkin gagal karena ketidaktepatan titik apung.

Cobalah online!

Bagaimana itu bekerja

P:×ⱮP%PĠẈḟ1Sʋ€iƓ  Main link. Argument: A (array)

P   P P           Yield the product of A.
 :                Divide the product by each n in A.
  ×Ɱ              Multiply the quotients by each k in [1, ..., prod(A)].
     %            Take the results modulo the product.
             €    Map the link to the left over the array of remainders.
            ʋ       Combine the links to the left into a dyadic chain.
       Ġ              Group indices of identical elements.
        Ẉ             Widths; yield the lengths of the groups.
         ḟ1           Filterfalse; remove all copies of 1.
           S          Take the sum.
               Ɠ  Read an integer j from STDIN.
              i   Find the first index of j in the array of sums.
Dennis
sumber
2

CJam, 42 34 33 byte

0{)_eas~@d\f/1f%7fmO$e`0f=1m1b-}g

Coba biola ini atau test suite ini dalam juru bahasa CJam.

Bagaimana itu bekerja

0       e# Push 0 (accumulator).
{       e# Do:
  )_    e#   Increment the accumulator and push a copy.
  eas~  e#   Push the command-line args, flatten and evaluate.
        e#   This pushes a number and an array.
  @d    e#   Rotate the accumulator copy on top and cast to Double.
  \f/   e#   Divide it by each of the integers in the array.
  1f%   e#   Get the fractional part of each result.
  7fmO  e#   Round all fractional parts to seven decimal digits.
  $e`   e#   Sort and perform run-length encoding.
  0f=   e#   Select the lengths of the runs.
  X-    e#   Discard runs of length 1.
  Xb    e#   Compute the sum of the remaining runs.
  -     e#   Subtract the sum from the input number (target).
}g      e# If this pushes a non-zero value, we've missed the target;
        e# repeat the loop.
Dennis
sumber
1

Jelly , 15 byte

÷_:ĠẈḟ1S⁼⁴
1ç1#

Cobalah online!

program penuh.

Menderita ketidaktepatan titik apung.

Erik the Outgolfer
sumber